Run Time Check Failure #2, AND array values swapped with outputs incorrectly

I've been struggling with this piece for a while now. I've googled run time check failure and I have no idea what to do. From what I get, it's because I declared swapEven and swapOdd to have an array of size 0? I initially had this set up as a pointer array, but that just didn't work. Can anybody point me in the right direction please? Thanks in advance!

void arrangeArrayJesseRagsdale(int* ary1, int* ary2, int arraySize1, int arraySize2) {
  int i, j;
  int temp;
  int swap = 0;
  int* swapEven = 0;
  int* swapOdd = 0;

  swapEven = new int[arraySize1];
  swapOdd = new int[arraySize2];

  cout << "  Original Arrays\n    Array #1: ";
  for (i = 0; i < arraySize1; i++) {
    cout << ary1[i] << " ";
  }

  cout << endl << "    Array #2: ";
  for (i = 0; i < arraySize2; i++) {
      cout << ary2[i] << " ";
  }
  cout << endl;

  for (i = 0; i < arraySize1; i++) {
      for (j = 0; j < arraySize2; j++) {
      if (ary1[i] % 2 != 0) {
        if (ary2[j] % 2 == 0) {
          temp = swapOdd[i] = ary1[i];
          ary1[i] = swapEven[i] = ary2[j];
          ary2[j] = temp;
          swap++;
        }
      }
      }
  }

  cout << "\n  Updated Arrays\n    Array #1: ";
  for (i = 0; i < arraySize1; i++) {
    cout << ary1[i] << " ";
  }
  cout << endl << "    Array #2: ";
  for (i = 0; i < arraySize2; i++) {
    cout << ary2[i] << " ";
  }
  cout << endl;

  if (swap > 0) {
        cout << "\n  Swapping info -\n";
    for (i = 0; i < swap; i++) {
        cout << "    Array #1 value " << swapOdd[i] << " swapped with Array #2 value " << swapEven[i] << endl;
    }
  }

  cout << "\nThere is/are " << swap << " swap(s)." << endl << endl;

  delete[] swapEven;
  delete[] swapOdd;

  return;
}