return and move constructor [duplicate]

This question already has an answer here:

• Why is using the move constructor in a return statement legal? 2 answers

struct CAT
{
    CAT(){cout<<"CAT()"<<endl;}
    CAT(const CAT& ){cout<<"CAT(const CAT&)"<<endl;}
    CAT(CAT&& ){cout<<"CAT(CAT &&)"<<endl;}
    void speak(){cout<<"speak()"<<endl;}
};


CAT f()
{
    CAT local_c;
    return local_c;
}

int main()
{
    CAT c = f();
    c.speak();
}

I compile the code using -fno-elide-constructors which disabling g++'s return-value optimisation, so we can observe all the actions in the code.

Here is the output:

CAT()
CAT(CAT &&)
CAT(CAT &&)
speak()

what is confusing me is that the first output "CAT(CAT &&)". It is my understanding that local_c is a lvalue, so when compiler create the internal temporary CAT object, it should use CAT(const CAT&) instead of CAT(CAT&&), right?