How to pass exact memory size to free() if void* allocation size is known

As far as I know ; In c++ and c delete operator or free() function can know the size of allocated memory from pionter data type and delete can call the destructor automatically.

If the allocated pointer is registered using a kind of singleton static dynamic array which don't use new operator in its mechanism (ie. malloc only) in oveloaded new pointer. this array register void* pointers and take the size of that pointer from overloaded new operator

Ex.

void * operator new (size_t sz) {
  void * m = malloc (sz);
  Dynamic_Array::get_instance()->add(m,sz) ; //registering  pointer
  return m ;
}

so My question is how to use the information about size to release the exact allocated memory that I forget to delete using the destructor of this array.

Ex.

Dynamic_Array::~Dynamic_Array() {
  int index = 0;
  while(index < storage_size) //storage_size: total number of pointers in array 

 /* storage is void** array which  register 
   allocated pointers as void* and use classic memset and memcpy to enlarge*/

    {
      if (storage[index] != NULL) printf("Pointer : %d was not deleted\n", storage[index]);
//how to use delete or free here to delete void* pointer  but with known size of memory
      index ++;
      }
}

Thank you.